Помогите решить пожалуйстаа
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1 2 1)6/(y-3)(y+3)-1/(y-3)=(6-y-3)/(y-3)(y+3)=3-y)/(y-3)(y+3)=-1/(y+3) 2)-1/(y+3)*(y+3)²/5=-(y+3)/5 3 1)2/(x-2)(x+2)-1/x(x-2)=(2x-x-2)/x(x-2)(x+2)=(x-2)/x(x-2)(x+2)=1/x(x+2) 2)1/x(x+2): 1/(x+2)²=1/x(x+2)*(x+2)²=(x+2)/x