X+4xy+y=6x^2y+xy^2=2это системаОЧЕНЬ СРОЧНО

Решите задачу:

$x+4xy+y=6\\ x^2y+xy^2=2\\ \\ x+y+4xy=6\\ xy(x+y)=2\\ \\ x+y=6-4xy\\ xy(6-4xy)=2\\ \\ xy=t\\ 6t-4t^2=2\\ 4t^2-6t+2=0\\ D=36-4*4*2=2^2\ t_{1}=\frac{6+2}{8}=1\\ t_{2}=\frac{6-2}{8}=\frac{1}{2}\\ xy=1\\ xy=0.5$

$xy=1\\ xy=0.5\\ \\ 1)\\ x+4xy+y=6\\ xy=1\\ \\ x=\frac{1}{y}\\ \frac{1}{y}+4+y=6\\ 4y+y^2-6y+1=0\\ y^2-2y+1=0\\ (y-1)^2=0\\ y=1\\ x=1\\ \\ 2)\\ x+4xy+y=6\\ xy=0.5\\ \\ x=\frac{0.5}{y}\\ \frac{0.5}{y}+4*0.5+y=6\\ 0.5+2y+y^2-6y=0\\ y^2-4y+0.5=0\\ D=\sqrt{56}\\ y_{1}=-\frac{\sqrt{14}-4}{2}\\ y_{2}=\frac{\sqrt{14}+4}{2}\\ x_{1}=-\frac{\sqrt{14}+8}{4\sqrt{14}-18}\\ x_{2}=-\frac{ \sqrt{14}-8}{4\sqrt{14}+18}$