Помогите вычислить интеграл
3 1 3 1 3 1 3 ∫ x/(x^2 - 1) dx = --- ∫ d(x^2)/(x^2 - 1) = --- ∫ d(x^2 - 1)/(x^2 - 1) = -- ln (x^2 - 1) | = √2 2 √2 2 √2 2 √2 = (1/2) * ln(3^2 - 1) - (1/2) * ln((√2)^2 - 1) = (1/2) * ln 8 - (1/2) * ln 1 = ln (8^(1/2 )) = = ln √8 ≈ 1.0397