Дано
m(CaHCO3)=240 kg=240000 g
W()=20%
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V(CO2)-?
m(Ca(HCO3)2)=240000-(240000*20%/100%)=192000 g
192000 X
Ca(HCO3)2-->CaO+H2O+2CO2 M(Ca(HCO3)2)=162 g/mol Vm=22.4L/mol
162 2*22.4
X=19200*44.8 / 162
X=53096.3 g = 53,096 kg
ответ 53.096 кг