1)-5 (3а+1)-11=-16 2)3(х-5)+10=2 (3+х)-14

Question

1)-5 (3а+1)-11=-16
2)3(х-5)+10=2 (3+х)-14

Answer 1

1)-5 (3а+1)-11=-16
-15a - 5 - 11 = -16
-16a = -16 + 16
16a = 0
a = 0
2)3(х-5)+10=2 (3+х)-14
3x - 15 + 10 = 6 + 2x - 14
3x - 2x = 6 - 14 + 15 - 10
x = -3

Answer 2

2)
3х-15+10=6+2х-14
3х-2х=6-14-10+15
х=-3
1)
-15а-5-11=-16
-15а=-16+5+11
-15а=0
а=0