(1/27×125^-1)^-1/3+3/4-(2/3)^-1 Решение

Question

(1/27×125^-1)^-1/3+3/4-(2/3)^-1
Решение

Comments

условие точное ?

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3/4 - (2/3)^-1 между дробями минус?

Answer 1

(1/27×125⁻¹)⁻¹/³+3/4-(2/3)⁻¹=(27⁻¹×125⁻¹)⁻¹/³+3/4-(2/3)⁻¹=27¹/³×125¹/³ +3/4-3/2=

= ∛3³ ×∛5³ -3/4 =3*5-3/4=14 1/4

Comments

Спасибо