Докажите что функция f есть первообразная для функции f на промежутке: 1. f(x)=x^5, f(x)=5x^4, x ∈(-∞;∞) 2. f(x)=x^-3, f(x)=-3x^-4, x ∈(0;∞) 3. f(x)=1/7x^7, f(x)=x^6, x ∈(-∞;∞) 4. f(x)=-1/6x^-6, f(x)=x^-7, x ∈(0;∞)
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Спасибо! :)