2 log 99 3 + logg 99 11

Question

2 log 99 3 + logg 99 11

Answer 1

Log a b + log a c = log a (bc)
2log₉₉ 3 + log₉₉ 11 = log₉₉ 3² + log₉₉ 11 = log₉₉ 9 + log₉₉ 11 = log₉₉ 99 = 1