F(x)=2sinx+4cosx-tgx. x=п/6

Question

F(x)=2sinx+4cosx-tgx. x=п/6

Answer 1

F(x)=2sinx+4cosx-tgx , x=π/6
F(π/6)=2sin(π/6)+4cos(π/6)-tg(π/6)=2.1/2 +4.√3/2-√3/3=
=1+2√3-√3/3=1+5√3/3=(3+5√3)/3