Сократите дробь 5x-x^2/5+34x-7x^2
5x-x^2/5+34x-7x^2=x(5-x)/-7x²+34x+5 -7x²+34x+5=0 7x²-34x-5=0 D=34²+5*7*4=1156+140=1296 √1296=36 x1=1/14[34+36]=5 x2=1/14[34-36]=-2/14=-1/7 -7x²+34x+5=-(7x+1)(x-5) = (7x+1)(5-x) x(5-x)/(7x+1)(5-x)=x/(7x+1)