(2x²+7.5x-7)²-(x²+9.5x+1)²<0<br>(2x²+7.5x-7-x²-9.5x-1)(2x²+7.5x-7+x²+9.5x+1)=
=(x²-2x-8)(3x²+17x-6)<0<br>x²-2x-8=0 x1=4 x2=-2 по т. Виета
3x²+17x-6=0 D=289+72=361 √361=19
x1=1/6[-17-19]=-6 x2=1/6[-17+19]=1/3
(x-4)(x+2)(x+6)(x-1/3)<0<br>
------------- -6------------- -2--------------1/3---------------4---------------
+ - + - +
x∈(-6;-2)∪(1/3;4) целые решения -5-4-3+1+2+3= -6