log7(x)+log49(36)=log1/7(2x+6)+log7(48)
log(1/a)x=-log(a)x
log(a^n)b^n=log(a)b
ОДЗ
{x>0
{2x+6>0⇒x>-3
x∈(0;∞)
log(7)x+log(7)6=-log(7)(2x+6)+log(7)48
log(7)x+log(7)(2x+6)=log(7)48-log(7)6
log(7)[x(2x+6)]=log(7)(48/6)
log(7)(2x²+6x)=log(7)8
2x²+6x=8
x²+3x-4=0
x1+x2=-3 U x1*x2=-4
x1=1 U x2=-4∉ОДЗ
Ответ х=1