F(x)=(5/√(4x-12))-(7/(x^2-16)) f(x)=(x^2-2)/(x^2-7) производная помогите плизз

Решите задачу:

$(\frac{5}{\sqrt{4x-12}}-\frac{7}{x^2-16})'=(\frac{5}{\sqrt{4x-12}})'-(\frac{7}{x^2-16})'=\\(\frac{5}{2}*\frac{1}{\sqrt{x-3}})'-(7*\frac{1}{x^2-16})'=\frac{5}{2}[(\sqrt{x-3})^{-1}]'-7[(x^2-16)^{-1}]'=\\\frac{5}{2}[-1*(\sqrt{x-3})^{-2}(x-3)']-7[-1*(x^2-16)^{-2}(x^2-16)']=\\-\frac{5}{2}(x-3)^{-1}+14x(x^2-16)^{-2}$

$(\frac{x^2-2}{x^2-7})'=\frac{(x^2-2)'(x^2-7)-(x^2-2)(x^2-7)'}{(x^2-7)^2}=\frac{2x(x^2-7)-(x^2-2)2x}{(x^2-7)^2}=-\frac{10x}{(x^2-7)^2}$