B) Simplify the expression 3√2+2√3 / 3√2− 2√3 Write your answer in its simplest form of a...

Решите задачу:

$\frac{3 \sqrt{2} +2 \sqrt{3} }{3 \sqrt{2} -2 \sqrt{3} } = \frac{(3 \sqrt{2} +2 \sqrt{3} )(3 \sqrt{2} +2 \sqrt{3} )}{(3 \sqrt{2} -2 \sqrt{3} )(3 \sqrt{2} +2 \sqrt{3} )} = \frac{18+12 \sqrt{6}+12 }{9*2-4*3}= \frac{30+12 \sqrt{6} }{6}= \\ \\ = \frac{6(5+2 \sqrt{6}) }{6}= 5+2 \sqrt{6}$