40 балловАлгебра 10 классРешите пожалуйста

$sin \alpha =[tex] \frac{3 \pi }{4} =$ \frac{ \sqrt{2} }{y2} ;[/tex]

$sin \alpha = [tex] \frac{11 \pi }{6} =$ -1/2;[/tex];
$\frac{13 \pi }{3} = \frac{ \sqrt{3} }{2} ;$ sin\alpha =2 \pi =0'[/tex]

sin $\frac{9 \pi }{2} =1$ ; sin(-π)=0; sin(7π/3) = √3/2;

cos(3π/4) =- √2/2; cos(11π/6) =√3/2; cos(13π/3) =1/2; cos2π =1;
cos(9π/2) =0; cos(-π)= 1; cjs(7π/3) =1/2;
tg(3π/4)=-1; tg(11π/6) =-√3/3; tg(2π) =0; tg(9π/2) =∅; tg(-π) 0;
tg(7π/3) = √3/3; tg(13π/3) =√3;
ctg(3π/4) =-1; ctg(11π/6) =-√3; ctg(13π/3) =√3/3; ctg(2π) =∅;
ctg(9π/2) = -0; ctg(-π) =∅; ctg(7π/3)=√3/3;