Помогите пожалуйста log3(8x^2+x)> 2+log3 x^2+log3 x

Решите задачу:

$\log_3(8x^2+x) \ \textgreater \ 2 + \log_3(x^2) + \log_3(x)\\ \log_3(8x^2+x) \ \textgreater \ \log_3(9) + \log_3(x^2) + \log_3(x)\\ \log_3(8x^2+x) \ \textgreater \ \log_3(9x^3) \\ 8x^2+x \ \textgreater \ 9x^3\\ 9x^3-8x^2-x\ \textless \ 0\\ x(9x^2-8x-1) \ \textless \ 0\\ x \in (-\infty; -\frac{1}{9}) \cup (0;1)\\\\ 8x^2+x \ \textgreater \ 0\\ x(8x+1) \ \textgreater \ 0\\ x \in (-\infty; -\frac{1}{8}) \cup (0; +\infty)\\\\ x \ \textgreater \ 0\\ x \in (0; +\infty)\\\\ x \in ((-\infty; -\frac{1}{9}) \cup (0;1)) \cap ((-\infty; -\frac{1}{8}) \cup (0; +\infty)) \cap (0; +\infty)\\ x \in (0;1)$