3x-2корень x-8=0 помогите плиз
3x-20, 3y^{2}-2y-8=0, D=100, y_{1}=2, y_{2}=-\frac{4}{3}, \sqrt{y}=2, y=4" alt="3x-2\sqrt{x}-8=0, \sqrt{x}=y, y>0, 3y^{2}-2y-8=0, D=100, y_{1}=2, y_{2}=-\frac{4}{3}, \sqrt{y}=2, y=4" align="absmiddle" class="latex-formula">
3x2 - 2x - 8 = 0 D = b2 - 4ac D = 4 + 96 = 100 = 10
x1,2 = -b ± √D x1 = 2 + 10/6= 12/6= 2 x2 = 2 - 10/6 = - 8/6= - 4/3 Ответ: x1 = 2 ; x2 = - 4/3
0, 3y^{2}-2y-8=0, D=100, y_{1}=2, y_{2}=-\frac{4}{3}, \sqrt{y}=2, y=4" alt="3x-2\sqrt{x}-8=0, \sqrt{x}=y, y>0, 3y^{2}-2y-8=0, D=100, y_{1}=2, y_{2}=-\frac{4}{3}, \sqrt{y}=2, y=4" align="absmiddle" class="latex-formula">