(x-5)(x-2)²(x+1)=112

Question

(x-5)(x-2)²(x+1)=112

Answer 1

(х^2-4х-5)(х^2-4х+4)=112
x^2-4x=t
(t-5)(t+4)=112
t^2-t-20-112=0
t^2-t-132
D=1+4*132=529
✓D=23
t1=1-23/2=-11
t2=1+23/2=12
[x^2-4x+11=0
]x^2-4x-12=0
1)D=4-11<0<br>Корней нет
2)D=4+12=16
✓D=4
x1=2-4=-2
x2=2+4=6
Ответ:-2;6