(15 целых 5/9 - 9 целых 25/27) - (7 целых 2/9 - 5 целых) =

Решите задачу:

$(15\frac{5}{9} - 9 \frac{25}{27} )-(7 \frac{2}{9} -5)=3 \frac{11}{27}$

$1) 15 \frac{5}{9} - 9\frac{25}{27} =15 \frac{15}{27} -9 \frac{25}{27} = 14 \frac{42}{27} -9 \frac{25}{27} =5 \frac{17}{27}$

$2) 7 \frac{2}{9} -5=2 \frac{2}{9}$

$3) 5 \frac{17}{27} -2 \frac{2}{9} =5 \frac{17}{27} -2 \frac{6}{27} =3 \frac{11}{27}$