Помогите решить 35.7 - 35.9

35.7
a) $\sqrt[4]{x^2}=x^{ \frac{2}{4} } =x^{ \frac{1}{2} }= \sqrt{x}$
б) $\sqrt[6]{y^4} =y^{ \frac{4}{6} }=y^ \frac{2}{3}= \sqrt[3]{y^2}$
в) $\sqrt[10]{a^5}=a^ \frac{5}{10}=a^ \frac{1}{2}= \sqrt{a}$
г) $\sqrt[24]{n^{16}} =n^ \frac{16}{24}=n^ \frac{2}{3}= \sqrt[3]{n^2}$
35.8
а) $\sqrt[4]{b^8} =b^ \frac{8}{4} =b^2$
б) $\sqrt{l^6} =l^ \frac{6}{2}=l^3$
в) $\sqrt[5]{d^{15}} =d^ \frac{15}{5}=d^3$
г) $\sqrt[3]{t^{12}}=t^ \frac{12}{3}=t^4$
35.9
а) $\sqrt{a^2b^4} =(a^2b^4)^ \frac{1}{2}=a^ \frac{2}{2}b^ \frac{4}{2} =ab^2$
б) $\sqrt[3]{a^3b^6}=(a^3b^6)^ \frac{1}{3}=a^ \frac{3}{3}b^ \frac{6}{3}=ab^2$
в) $\sqrt[4]{a^4b^8} =(a^4b^8)^ \frac{1}{4}=a^ \frac{4}{4}b^ \frac{8}{4}=ab^2$
г) $\sqrt[5]{a^5b^{15}}=(a^5b^{15})^ \frac{1}{5} =a^ \frac{5}{5}b^ \frac{15}{5}=ab^3$