5\x^3 = 2m^3\n^5= 1\a^3b^2= 2x\a-b= a\b= p^5\q^4= 7^3*7^-2= 2÷2^-2= (3^-1)^2= ...

Question

5\x^3 =
2m^3\n^5=
1\a^3b^2=
2x\a-b=
a\b=
p^5\q^4=


7^3*7^-2=
2÷2^-2=
(3^-1)^2=
(5^-2)^-1=
8^-2*4^3=
10^0÷10^-3=
10^8*10^-5*10^-4=
3^-6 * (3^-2)^-4

Answer 1

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