Помогите решить систему уравнений:)

Решите задачу:

$\left \{ {{6(y-x)-50=y} \atop {y-xy=24}} \right. \\ \\ \left \{ {{5y-6x=50} \atop {y(1-x)=24}} \right. \\ \\ \left \{ {{5y-6x=50} \atop {y=\frac{24}{1-x}}} \right.\\ \\ \left \{ {{ \frac{5*24}{1-x}-6x=50} \atop { y=\frac{24}{1-x}}} \right\\ 120-6x(1-x)=50(1-x)\\ 120-6x+6x^2=50-50x\\ 6x^2+44x+70=0\\ D=8^2\\ x=-5\\ x=-\frac{7}{3}\\ y=4\\ y=\frac{24}{1+\frac{7}{3}}=7.2$