A)log6(12)+log6(x)=log6(24)б)log2(3x)=log2(4)+log2(6)

Question

A)log6(12)+log6(x)=log6(24)
б)log2(3x)=log2(4)+log2(6)

Answer 1

A) log6(12)+log(6x)=log6(24)
log6(12x)=log6(24)
12x=24
x=2
б) log2(3x)=log2(4)+log2(6)
log2(3x)=log2(24)
3x=24
x=8