3^x * 2^y = 72
3^x + 2^y = 17
----
3^x=a > 0
2^y=b >0
---
ab=72
a+b=17
---
a=17-b
b(17-b)=72
b²-17b+72=0
D=17²-4*72=289 - 288 = 1
b12=(17+-1)/2 = 8 9
b1=8 a1=9
3^x=9 3^x=3^2 x=2
2^y=8 2^y=2^3 y=3
b2=9 a2=8
3^x=8 x=log(3) 8 = 3log(3) 2
2^y=9 y=log(2)9 = 2log(2) 3
ответ (2 3) ( 3log(3) 2 2log(2) 3)