1.2.3.3.4.5.6. x1 . Xn =(2 n+1)*3

Question

1.2.3.3.4.5.6. x1 . Xn =(2 n+1)*3

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Answer 1

X_1 = (2*1 + 1)*3 = 3*3 = 9

x_2 = (2*2 + 1)*3 = 5*3 = 15

x_3 = (2*3 + 1)*3 = 7*3 = 21

x_4 = (2*4 + 1)*3 = 9*3 = 27

x_5 = (2*5 + 1)*3 = 11*3 = 33

x_6 = (2*6 + 1)*3 = 13*3 = 39