X^2+2x-80 через дискриминант
X2+2x-80=0 x2+2x-80 = 0D = b2 - 4ac = ( + 2)2 – 4·1·( – 80) = 324 x1 = -b + √ D = -2 + √ 324 = -2 + 18 = 16 = 8 x2 = -b – √ D = -2 – √ 324 = -2 – 18= -20/2= -10
Нормально ?
Сойдёт?