Решение системы лин.уравнения методом Краммера: {X + 2y + 3z = 1 2x - y + 2z = 6 x + y +5z = -1
где дельты там определители а не матрицы
А зачем ответ, то есть столбец X, Вы написали где-то посередине слева? Разве не лучше написать его в конце?
а съехало так
![X=\left[\begin{array}{ccc}4\\0\\-1\end{array}\right]](https://tex.z-dn.net/?f=++X%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%5C%5C0%5C%5C-1%5Cend%7Barray%7D%5Cright%5D+ "X=\left[\begin{array}{ccc}4\\0\\-1\end{array}\right]")
![A= \left[\begin{array}{ccc}1&2&3\\2&-1&2\\1&1&5\end{array}\right]
B= \left[\begin{array}{ccc}1&\\6\\-1\end{array}\right]
det A = delta = -5+6+4+3-2-20= -14 =/= 0
delta 1 = \left[\begin{array}{ccc}1&2&3\\6&-1&2\\-1&1&5\end{array}\right] = -5-4+18-3-2-60 =-56
delta 2 = \left[\begin{array}{ccc}1&1&3\\2&6&2\\1&-1&5\end{array}\right] =30+2-6-18+2-10=0
delta 3 = \left[\begin{array}{ccc}1&2&1\\2&-1&6\\1&1&-1\end{array}\right]=1+12+2+1-6+4=14](https://tex.z-dn.net/?f=A%3D+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C2%26-1%262%5C%5C1%261%265%5Cend%7Barray%7D%5Cright%5D%0AB%3D+++++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26%5C%5C6%5C%5C-1%5Cend%7Barray%7D%5Cright%5D+%0A+%0Adet+A+%3D+delta+%3D+-5%2B6%2B4%2B3-2-20%3D+-14+%3D%2F%3D+0%0A%0Adelta+1++%3D+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C6%26-1%262%5C%5C-1%261%265%5Cend%7Barray%7D%5Cright%5D++%3D+-5-4%2B18-3-2-60+%3D-56%0A%0Adelta+2+%3D+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%261%263%5C%5C2%266%262%5C%5C1%26-1%265%5Cend%7Barray%7D%5Cright%5D+%3D30%2B2-6-18%2B2-10%3D0%0A%0Adelta+3+%3D+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%261%5C%5C2%26-1%266%5C%5C1%261%26-1%5Cend%7Barray%7D%5Cright%5D%3D1%2B12%2B2%2B1-6%2B4%3D14 "A= \left[\begin{array}{ccc}1&2&3\\2&-1&2\\1&1&5\end{array}\right]
B= \left[\begin{array}{ccc}1&\\6\\-1\end{array}\right]
det A = delta = -5+6+4+3-2-20= -14 =/= 0
delta 1 = \left[\begin{array}{ccc}1&2&3\\6&-1&2\\-1&1&5\end{array}\right] = -5-4+18-3-2-60 =-56
delta 2 = \left[\begin{array}{ccc}1&1&3\\2&6&2\\1&-1&5\end{array}\right] =30+2-6-18+2-10=0
delta 3 = \left[\begin{array}{ccc}1&2&1\\2&-1&6\\1&1&-1\end{array}\right]=1+12+2+1-6+4=14")