РЕШИТЕ ПРЕДЕЛ ПОЖАЛУЙСТА

Решите задачу:

$\displaystyle \lim_{x \to 2} \frac{\sqrt{4x+1}-3}{\sqrt{3x+10}-4}=\frac{0}{0}=\\=\lim_{x \to 2} \frac{\sqrt{4x+1}-3}{\sqrt{3x+10}-4}*\frac{(\sqrt{4x+1}+3)(\sqrt{3x+10}+4)}{(\sqrt{4x+1}+3)(\sqrt{3x+10}+4)}=\\=\lim_{x \to 2}\frac{(4x-8)(\sqrt{3x+10}+4)}{(3x-6)(\sqrt{4x+1}+3)}=\frac{4}{3}\lim_{x \to 2}\frac{\sqrt{3x+10}+4}{\sqrt{4x+1}+3}=\frac{4}{3}*\frac{8}{6}=\frac{16}{9}$