Помогите (1+5y)^2-5×(1+5y)×y=10 Срочно
1 + 10у + 25у^2 - 5y - 25y^2 = 10 1 + 5y = 10 5y = 10 - 1 5y = 9 y = 1,8
(1+5y)²-5(1+5y)y=10 (1+5y)(1+5y-5y)=10 1+5y=10 5y=9 y=9/5 y=1,8 ili (1+5y)²-5(1+5y)y=10 1+10y+25y²-5y-25y²=10 1+5y=10 5y=9 y=1,8