2.
дано
n(HCL)=17.72 mol
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V(HCL)-?
V(HCL)=n(HCL)*Vm= 17.72*22.4 = 397 л
ответ 397 л
3.
дано
N(H2O)=10.836*10^23 молекул
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V(H2O)-?
V(H2O) / Vm = N(h2O) / N(A)
V(H2O) = Vm*N(H2O) / N(A)
V(H2O) = 22.4*10.836*10^23 / 6.02*10^23 = 40.32 L
ответ 40.32 л
4.
дано
V(C3H6)=71.68 L
----------------------------
N(C3H6)-?
m(C3H6)-?
V/Vm = N/N(A)
N(C3H6)=V(C3H6)*N(A) / Vm
N(C3H6)=71.68*6.02*10^23 / 22.4 = 19.264 *10^23 молекул
V(C3H6) / Vm = m(C3H6) / M(C3H6) M(C3H6)=42 g/mol
m(C3H6)= M(C3H6)*V(C3H6) / Vm = 42*71.68 / 22.4 = 134.4 g
ответ 19.264 *10^23 молекул, 134.4 г