Пожалуйста памагите решить номер 42 и 43

42.
$1)........= \sqrt{ \frac{ \sqrt{ (65-56)(65+56)}}{(57-24)(57+24)} }= \sqrt{ \frac{ \sqrt{121*9} }{33*81} } = \sqrt{ \frac{33}{33*81} } = \sqrt{ \frac{1}{81} } = \frac{1}{9} \\ \\ 2)......= \sqrt{ \frac{(3.02-2.98)(3.02+2.98)}{ \sqrt{(40-32)(40+32)} } } = \sqrt{ \frac{0.04*6}{ \sqrt{2*4*2*36} } } = \sqrt{ \frac{0.04*6}{4*6} } =0.1 \\ \\ 3).......= \sqrt{ \frac{0.7 \sqrt{0.09} }{ \sqrt{0.07*0.63} } }= \sqrt{ \frac{0.7*0.3}{0.7*0.3} } = \sqrt{1} =1$ $. \\ \\ 4)......= \sqrt{ \frac{66 \sqrt{900} }{ \sqrt{3025} } } = \sqrt{ \frac{66*30}{55} } = \sqrt{36}=6$

43.
1)
(2√5)²=4*5=20 (4)
(√3)^4=3²=9 (2)
(√5)²=5 (1)
(-3√2)²=9*2=18 (3)

2)
(-7)²=49 (4)
-(-√6)²= -6 (1)
(-2√2)²=4*2=8 (3)
(√0.5)^4=0.5²=0.25 (2)

3)
-4√2²= -4*2= -8 (3)
(4√2)²=16*2=32 (4)
-(2√3)²= - 4*3= -12 (1)
-√11²= -11 (2)

4)
(√8)²=8 (3)
√((-5)²)=√25=5 (2)
(-(-√3)²)²=9 (4)
-(-√2)^6= -2³= -8 (1)