Решите только примеры с умножением

Решите задачу:

$\frac{( {a}^{2} - 1) }{a - b} \times \frac{9a - 9b}{ {a}^{2} + a} = \frac{(a - 1)(a + 1)}{a - b} \times \frac{9(a - b)}{a(a + 1)} = \frac{9(a - 1)}{a}$
$\frac{ {(x + 4)}^{2} }{3x - 9} \times \frac{ {x}^{2} - 9}{3x + 12} = \frac{ {(x + 4)}^{2} }{3(x - 3)} \times \frac{(x - 3)(x + 3)}{3(x + 4)} = \frac{(x + 4)(x + 3)}{9}$
$\frac{ {(y - 5)}^{2} }{y} \times \frac{7 {y}^{2} }{ {y}^{2} - 25} = \frac{ {(y - 5)}^{2} }{1} \times \frac{7y}{(y - 5)(y + 5)} = \frac{7y(y - 5)}{y + 5}$
$\frac{ {m}^{2} - {n}^{2} }{9m} \times \frac{3 {m}^{2} }{m - n} = \frac{(m - n)(m + n)}{3} \times \frac{m}{m - n} = \frac{m(m + n)}{3}$
$\frac{ {x}^{2}y }{25 {y}^{2} - 4 } \times \frac{15y + 6}{3x {y}^{2} } = \frac{x}{(5y - 2)(5y + 2)} \times \frac{3(5y + 2)}{3y} = \frac{3x}{y(5y - 2)}$

$\frac{24d{c}^{2} }{9 {p}^{2} - 25} \times \frac{5 - 3p}{12c {d}^{3} } = \frac{2c}{(3p - 5)(3p + 5)} \times - \frac{( 3p - 5)}{ {d}^{2} } = - \frac{2c}{ {d}^{2} (3p + 5)}$