Log(9)x = y
(3y+1) / (2y+3) <= 3 - y<br>((3y+1) + (y-3)(2y+3)) /(2y+3) <= 0<br>(3y+1 +2y^2 -6y +3y -9 ) / (2y+3) <= 0<br>(2y^2 -8) / (2y +3) <= 0<br>(y - 2)(y + 2) / (2y + 3) <= 0<br>
__-___[-2]__+__(-1,5)___-__[2]__+_
y <= -2 U -1,5 < y <= 2<br>
вернемся к замене:
log(9)x <= -2<br>x <= 9^(-2) = 1/81<br>
-1,5 < log(9)x <= 2<br>9^(-3/2) < x <= 9^2<br>1/27 < x <= 81<br>
Ответ: x <= 1/81 U 1/27 < x <= 81