Решите неравенство (x-4)/(x-3)≤0;

$\frac{(x-4)} {(x-3)} \leq 0$

$1) \left \{ {{(x-4)} \leq 0 \atop {(x-3)\ \textgreater \ 0}} \right.$

$\left \{ {{x} \leq 4 \atop {x\ \textgreater \ 3}} \right. \Rightarrow 3\ \textless \ x \leq 4$

2) $\left \{ {{(x-4)} \geq 0 \atop {(x-3)\ \ \textless \ \ 0}} \right.$

$\left \{ {{x} \ \geq \ 4 \atop {x\ \ \textless \ \ 3}} \right. \Rightarrow$ нет решения

Ответ: $3\ \textless \ x \leq 4$