Помогите решить две производные

1.
$y = {x}^{4} \sqrt{ {x}^{7} } \sqrt[3]{ {x}^{5} } = {x}^{4} {x}^{ \frac{7}{2} } {x}^{ \frac{5}{3} } = {x}^{4 + \frac{7}{2} + \frac{5}{3}} = {x}^{\frac{24 + 21 + 10}{6}} = {x}^{\frac{55}{6}} \\ \frac{dy}{dx} = \frac{55}{6} {x}^{\frac{49}{6}}$

2.
$f(x)=arcctg(\frac{2x}{1+x^2}) \\ f'(x)= -\frac{2(1+x^2) - 4x^2}{(1+x^2)^2} \times \frac{1}{1+(\frac{2x}{1+x^2})^2}$