√2*sin∧2 (π/2 + x) = - cosx

Question

√2*sin∧2 (π/2 + x) = - cosx

Answer 1

2sin²(3π/2 + x) = √3*cos(x)

2cos²(x) - √3*cos(x) = 0

cos(x) = 0 --> x = π/2 + πk

cos(x) = √3/2 --> x = ±π/6 + 2πk

Ответ: {π/2 + πk; ±π/6 + 2πk\ k - целое}.

Comments

спасибо

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откуда 3?