Sin(π+t)+cos(π/2)+t=√2

Question

Sin(π+t)+cos(π/2)+t=√2

Answer 1

Sin(π + t) + Cos(π/2 + t) = √2
- Sint - Sint = √2
- 2Sint = √2
Sint = - √2/2
t = (-1)ⁿarcSin(-√2/2) + πn,n ∈ z
t = (-1)ⁿ⁺¹π/4 + πn, n ∈ z