Найдите значения выражений: 1/5 - 1/6; 3/4 - 1/3; 7/9 - 2/11; 3/4 - 4/9; 7/8 - 5/12;...

Решите задачу:

$\frac{1}{5} - \frac{1}{6} = \frac{1*6}{5*6} - \frac{1*5}{6*5}= \frac{6}{30} - \frac{5}{30}= \frac{1}{30} \\ \\ \frac{3}{4} - \frac{1}{3} = \frac{3*3}{4*3} - \frac{1*4}{3*4}= \frac{9}{12} - \frac{4}{12}= \frac{5}{12} \\ \\ \frac{7}{9} - \frac{2}{11} = \frac{7*11}{9*11} - \frac{2*9}{11*9} =\frac{77}{99} - \frac{18}{99}= \frac{59}{99} \\ \\$

$\frac{3}{4} - \frac{4}{9} = \frac{3*9}{4*9} - \frac{4*4}{9*4} = \frac{27}{36} - \frac{16}{36}= \frac{11}{36} \\ \\ \frac{7}{8} - \frac{5}{12} =\frac{7}{4*2} - \frac{5}{4*3}= \frac{7*3}{4*2*3} - \frac{5*2}{4*3*2}= \frac{21}{24} - \frac{10}{24} = \frac{11}{24} \\ \\ \frac{11}{12} - \frac{11}{18} = \frac{11}{6*2} - \frac{11}{6*3}=\frac{11*3}{6*2*3} - \frac{11*2}{6*3*2}= \frac{33}{36} - \frac{22}{36} = \frac{11}{36}$