Решите пожалуйста бумажку по алгебре 8 класс
= - \frac{2( a^{2}+9 )}{a-9} * \frac{a-9}{3( a^{2} +9 )} = -2/3; 2) =
Ещё пж
![\frac{5 x^{2} +5x-10x}{x+1 }* \frac{4(x+1) }{15(x-1)}
= \frac{5 x^{2} -5x}{x+1} * \frac{4(x+1}{15(x-1)} = \frac{x(x-1)}{x+1} * \frac{4(x+1)}{15(x-1)} =4/3;\\3) [tex] \frac{5a}{a+3 } - \frac{45}{3a(a+3)} = \frac{5 x^{2} -45}{a(a+3)} = \frac{5(a-3)(a+3)}{a(a+3)} = \frac{5(a-3)}{a}](https://tex.z-dn.net/?f=+%5Cfrac%7B5+x%5E%7B2%7D+%2B5x-10x%7D%7Bx%2B1+%7D%2A+%5Cfrac%7B4%28x%2B1%29+%7D%7B15%28x-1%29%7D+%0A+%3D+%5Cfrac%7B5+x%5E%7B2%7D+-5x%7D%7Bx%2B1%7D+%2A+%5Cfrac%7B4%28x%2B1%7D%7B15%28x-1%29%7D+%3D++%5Cfrac%7Bx%28x-1%29%7D%7Bx%2B1%7D+%2A+%5Cfrac%7B4%28x%2B1%29%7D%7B15%28x-1%29%7D++%3D4%2F3%3B%5C%5C3%29%C2%A0%5Btex%5D+%5Cfrac%7B5a%7D%7Ba%2B3+%7D+-++%5Cfrac%7B45%7D%7B3a%28a%2B3%29%7D++%3D++%5Cfrac%7B5+x%5E%7B2%7D+-45%7D%7Ba%28a%2B3%29%7D+%3D++%5Cfrac%7B5%28a-3%29%28a%2B3%29%7D%7Ba%28a%2B3%29%7D+%3D+%5Cfrac%7B5%28a-3%29%7D%7Ba%7D++ "\frac{5 x^{2} +5x-10x}{x+1 }* \frac{4(x+1) }{15(x-1)}
= \frac{5 x^{2} -5x}{x+1} * \frac{4(x+1}{15(x-1)} = \frac{x(x-1)}{x+1} * \frac{4(x+1)}{15(x-1)} =4/3;\\3) [tex] \frac{5a}{a+3 } - \frac{45}{3a(a+3)} = \frac{5 x^{2} -45}{a(a+3)} = \frac{5(a-3)(a+3)}{a(a+3)} = \frac{5(a-3)}{a}")