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0" alt="(1 - \sqrt{3} )x \div ( \sqrt{3 + 1} ) > 0" align="absmiddle" class="latex-formula">
Умножим на (√3-1)
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0" alt="(1 - 2 \sqrt{3} + 3)x \div (1 - 3) > 0" align="absmiddle" class="latex-formula">
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0" alt="(2 - \sqrt{3} )x > 0" align="absmiddle" class="latex-formula">
2-√3>0, т. к. √4>√3
т.е.
(2-√3)х>0 при х>0
Ответ:(0;бесконечность)