48а при а=7,3 18а-18с+12-4с 2(5х-4)+10 8х+(х-5)-(3х-5) 5х(8х-(х-7)) 29-100х=0...

Question

48а при а=7,3
18а-18с+12-4с
2(5х-4)+10
8х+(х-5)-(3х-5)
5х(8х-(х-7))
29-100х=0
8х-(3-х)=8,1

Answer 1

1) 48a= 48*7,3= 350,4
2) 18a-18c+12-4c= 18a-22c+12
3) 2(5x+4)+10= 10x+8+10= 10x+18
4) 8x+(x-5)-(3x-5)= 8x+x-5-3x+5= 6x
5) 5x(8x-(x+7))= 5x(8x-x-7)= 40x²-5x²-35= 35x²-35
6) 29-100x=0
-100x= -29
100x=29
x=29/100= 0,29
x=0,29
7) 8x-(3-x)=8,1
8x-3+x=8,1
9x-3=8,1
9x=8,1+3
9x= 11,1
x= 1,2(3)= 37/30= 1 7/30
x= 1 7/30