Упростить выражение 8x/(8x+1)+3/(1-8x)-(64x^2+1)/(64x^2-1)

Решите задачу:

$\frac{8x}{8x+1}+ \frac{3}{1-8x}- \frac{64x^2+1}{64x^2-1}= \frac{8x}{8x+1}- \frac{3}{8x-1}- \frac{64x^2+1}{(8x+1)(8x-1)}=\\\\= \frac{8x(8x-1)-3(8x+1)-(64x^2+1)}{(8x+1)(8x-1)}=\frac{64x^2-8x-24x-3-64x^2-1}{(8x+1)(8x-1)}=\\\\=\frac{-32x-4}{(8x+1)(8x-1)}=\frac{-4(8x+1)}{(8x+1)(8x-1)}=- \frac{4}{8x-1}$