Kak rewat eto zadanya Pomagyte

1) $\frac{ \sqrt[4]{2} * \sqrt[4]{3} }{ \sqrt[4]{486} }+\sqrt[3]{27* (2 ^{2) ^{3} } } = \frac{ \sqrt[4]{2}* \sqrt[4]{3} }{ \sqrt[4]{2} * \sqrt[4]{3} * \sqrt[4]{81} } + \sqrt[3]{3 ^{3}* (2 ^{2}) ^{3} } = \frac{1}{3} + 3*4 = 12 \frac{1}{3}$
3) $\sqrt[3]{27 * 4^{3} } - \sqrt{ \frac{81}{256} } = \sqrt[3]{3 ^{3} * 4 ^{3} } - \frac{9}{16} = 3 * 4 - \frac{9}{16} = 12 - \frac{9}{16} = 11 \frac{7}{16}$