16x^3-32x^2-x+2=0 ..
16x³-32x²-x+2=0 16x²*(x-2)-(x-2)=0 (x-2)*(16x²-1)=0 x-2=0 x₁=2 16x²-1=0 (4x)²-1=0 (4x-1)*(4x+1)=0 4x-1=0 4x=1 x₂=1/4 4x+1=0 4x=-1 x₃=-1/4. Ответ: x₁=2 x₂=1/4 x₃=-1/4.
16x^3-32x^2-x+2=0 16x^2(x-2)-(x-2)=0 (x-2)(16x^2-1)=0 x1=2 x^2=1/16 x2=1/4 x3=-1/4