Help me!! Please! !!!!! 1) (3√5)^2= 2) √16b-0,5√36b= 3) 3x<7x+12=

Question

Help me!! Please! !!!!!
1) (3√5)^2=
2) √16b-0,5√36b=
3) 3x<7x+12=

Answer 1

1) (3√5)^2=3² * 5=9*5=45
2) √16b-0,5√36b=4√b  -  0.5*6√b=4√b  -  3√b = √b
3) 3x<7x+12<br>4x>-12
x>-3
x∈(-3;+∞)

Answer 2

1) (3√5)^2=3^2*√5^2=9*5=45
2)√16b-0,5√36b=4√b-0,5*6√b=4√b-3√b=√b
3)3x<7x+12<br> 3x-7x<12<br> -4x<12 |:-4<br> x>-3
Ответ: x>-3