Найдите числа х и у, удовлетворяющие равенству : x^{2} + 5 y^{2} + 4xy + 2y + 1 = 0

Question

Найдите числа х и у, удовлетворяющие равенству :

x^{2} + 5 y^{2} + 4xy + 2y + 1 = 0

Answer 1

I hope this helps you

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Comments

А можно чуть-чуть подробнее, начиная со второй строки?

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you have to do perfect square for this equation

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Oh, I see, okay, thanks

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if this perfect squares sum are equal zero each perfect square equal zero

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only imaginer numbers squares are negative

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sorry, but you made a mistake, there is not 4y ^ 2, but 5 y ^ 2

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no it's correct

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there are two perfect square

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4y^2+y^2=5y^2

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I could, thanks again