(1/3)^2:3-(-6/7)^0+(1/2)^-1

Question

(1/3)^2:3-(-6/7)^0+(1/2)^-1

Answer 1

(1/3)^2:3=1/9:3=1/9*1/3=1/27; (-6/7)^0=1; (1/2)^-1=(2^-1)^-1=2. получаем: 1/27-1+2=1 целая 1/27. Ответ: 1 целая 1/27.