Cos2α=? Когда ctgα=-1/3
Task/26087071 -------------------- cos2α - ? если ctgα = - 1/3 . ------- cos2α = (cos²α -sin²α) /(cos²α +sin²α) = (ctg²α -1) /(ctg²α +1) = =(1/9 -1) / (1/9 +1) =(1-9) / (1+9)= - 0,8. * * * ctq²α =(-1/3)² =1/9 * * *