Решить log3(x)+log√3(x)+log1/3(x)<6

Question

Решить
log3(x)+log√3(x)+log1/3(x)<6

Answer 1

log_3(x)+log_√3(x)+log_(1/3)(x)<6  ОДЗ х> 0

log_3(x)+log_3¹/²(x)+log_3⁻¹(x)<6<br>
log_3(x)+2log_3(x) - log_3(x)<6<br>

log_3(x)*(1+2-1)<6<br>

2log_3(x) <6<br>

log_3(x) < 3

х < 3³

х < 27

x∈(0;27)