Cos 2x=2 cos x-1 решите уравнение и найдите дискриминант
Cos2x = 2cosx - 1 2cos(^2)x - 1 = 2cosx - 1 2cos(^2)x - 2cosx = 0 cosx = t t∈[-1; 1] 2t^2 - 2t = 0 D = 4 - 0 = 4 t1 = 2 + 2 / 2 * 2 = 4/4 = 1 t2 = 2 - 2 / 2 * 2 = 0/4 = 0 cosx = 1 => x = +-π + 2πn, n∈Z cosx = 0 => x = +-π/2 + 2πn, n∈Z